What are the solutions to the equation 15t-1.86t^2=0 ?

The solutions to the equation 15t-1.86t^2=0 are t=0,t= 250/31

Find the zeros of 15t-1.86t^2=0

The zeros of 15t-1.86t^2=0 are t=0,t= 250/31

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15 t - 1.86 t^{2} = 0

t = 0, t = \frac{250}{31}

Solution steps

15 t - 1.86 t^{2} = 0

Multiply both sides by

100

1500 t - 186 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 186 t^{2} + 1500 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 1500 \pm 150 0 ^{2} - 4 ( - 186 ) \cdot 0}{2 ( - 186 )}

150 0^{2} - 4 (- 186) \cdot 0 = 1500

t_{1, 2} = \frac{- 1500 \pm 1500}{2 ( - 186 )}

Separate the solutions

t_{1} = \frac{- 1500 + 1500}{2 ( - 186 )}, t_{2} = \frac{- 1500 - 1500}{2 ( - 186 )}

t = \frac{- 1500 + 1500}{2 ( - 186 )} : 0

t = \frac{- 1500 - 1500}{2 ( - 186 )} : \frac{250}{31}

The solutions to the quadratic equation are:

t = 0, t = \frac{250}{31}

x^{2} = - 11

p - 2 = - 9

- 3 x + 3 < 6

2 (v + 1) = 10

3 x - 7 \leq 2

What are the solutions to the equation 15t-1.86t^2=0 ?
The solutions to the equation 15t-1.86t^2=0 are t=0,t= 250/31
Find the zeros of 15t-1.86t^2=0
The zeros of 15t-1.86t^2=0 are t=0,t= 250/31