What is log_{9}(10)-log_{9}(1/2)-log_{9}(4) ?

The solution to log_{9}(10)-log_{9}(1/2)-log_{9}(4) is log_{9}(5)

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simplify log_{9}(10)-log_{9}(1/2)-log_{9}(4)

simplify

lo g_{9} (10) - lo g_{9} (\frac{1}{2}) - lo g_{9} (4)

lo g_{9} (5)

Decimal Notation

0.73248 \dots

Solution steps

lo g_{9} (10) - lo g_{9} (\frac{1}{2}) - lo g_{9} (4)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{9} (10) - lo g_{9} (\frac{1}{2}) = lo g_{9} (\frac{10}{\frac{1}{2}})

= lo g_{9} (\frac{10}{\frac{1}{2}}) - lo g_{9} (4)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{9} (\frac{10}{\frac{1}{2}}) - lo g_{9} (4) = lo g_{9} (\frac{\frac{10}{\frac{1}{2}}}{4})

= lo g_{9} (\frac{\frac{10}{\frac{1}{2}}}{4})

\frac{\frac{10}{\frac{1}{2}}}{4} = 5

= lo g_{9} (5)

8.96 \cdot ln (\frac{87}{d - 78})

lo g_{4} (\frac{g}{64})

2 lo g_{10} (a) - 4 lo g_{10} (b)

lo g_{5} (4 x^{2})

lo g_{b} (x^{2}) y^{3}

What is log_{9}(10)-log_{9}(1/2)-log_{9}(4) ?
The solution to log_{9}(10)-log_{9}(1/2)-log_{9}(4) is log_{9}(5)