What is ln((df^5)/(\sqrt[3]{1-3d)}) ?

The solution to ln((df^5)/(\sqrt[3]{1-3d)}) is ln(d)+5ln(f)-ln(\sqrt[3]{1-3d})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln((df^5)/(\sqrt[3]{1-3d)})

simplify

Solution steps

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (d f^{5}) = ln (d) + ln (f^{5})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (f^{5}) = 5 ln (f)

3 lo g_{10} (2) + 2 lo g_{10} (3)

ln ((a b^{3})^{6})

2 ln (x + 4) - 7 ln (x)

lo g_{5} (25 x^{2})

lo g_{2} ((6 x)^{5})

What is ln((df^5)/(\sqrt[3]{1-3d)}) ?
The solution to ln((df^5)/(\sqrt[3]{1-3d)}) is ln(d)+5ln(f)-ln(\sqrt[3]{1-3d})