What is 1+log_{10}(Q)+log_{10}(2) ?

The solution to 1+log_{10}(Q)+log_{10}(2) is 1+log_{10}(2Q)

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simplify 1+log_{10}(Q)+log_{10}(2)

simplify

1 + lo g_{10} (Q) + lo g_{10} (2)

1 + lo g_{10} (2 Q)

Solution steps

1 + lo g_{10} (Q) + lo g_{10} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (Q) + lo g_{10} (2) = lo g_{10} (Q \cdot 2)

= 1 + lo g_{10} (Q \cdot 2)

= 1 + lo g_{10} (2 Q)

lo g_{c} (\frac{x ^{\frac{1}{2}} y ^{3}}{x ^{4}})

\frac{1}{4} lo g_{b} (x) + 3 lo g_{b} (y) - 5 lo g_{b} (x)

2 ln (x) - \frac{1}{3} ln (y) + 4 ln (z)

lo g_{2} (x^{3} y^{2})

lo g_{10} ((\frac{m}{n}) \cdot (\frac{p}{q}))

What is 1+log_{10}(Q)+log_{10}(2) ?
The solution to 1+log_{10}(Q)+log_{10}(2) is 1+log_{10}(2Q)