What are the solutions to the equation 5x^2+20x=-35 ?

The solutions to the equation 5x^2+20x=-35 are x=-2+sqrt(3)i,x=-2-sqrt(3)i

Find the zeros of 5x^2+20x=-35

The zeros of 5x^2+20x=-35 are x=-2+sqrt(3)i,x=-2-sqrt(3)i

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5 x^{2} + 20 x = - 35

x = - 2 + 3 i, x = - 2 - 3 i

Solution steps

5 x^{2} + 20 x = - 35

Move

35

to the left side

5 x^{2} + 20 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 5 \cdot 35}{2 \cdot 5}

Simplify

2 0^{2} - 4 \cdot 5 \cdot 35 : 103 i

x_{1, 2} = \frac{- 20 \pm 10 3 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 20 + 10 3 i}{2 \cdot 5}, x_{2} = \frac{- 20 - 10 3 i}{2 \cdot 5}

x = \frac{- 20 + 10 3 i}{2 \cdot 5} : - 2 + 3 i

x = \frac{- 20 - 10 3 i}{2 \cdot 5} : - 2 - 3 i

The solutions to the quadratic equation are:

x = - 2 + 3 i, x = - 2 - 3 i

3 x - 12 - 9 = 2 - x + 5

lo g_{4} (8) + lo g_{4} (5)

- 29 = 5 x + 6 - 12 x

x^{2} - x - 1

\frac{- 8}{- 4}

What are the solutions to the equation 5x^2+20x=-35 ?
The solutions to the equation 5x^2+20x=-35 are x=-2+sqrt(3)i,x=-2-sqrt(3)i
Find the zeros of 5x^2+20x=-35
The zeros of 5x^2+20x=-35 are x=-2+sqrt(3)i,x=-2-sqrt(3)i