What is simplify-log_{10}(1.32*10^{-3}) ?

The solution to simplify-log_{10}(1.32*10^{-3}) is -log_{10}(1.32)+3

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simplify-log_{10}(1.32*10^{-3})

simplify

- lo g_{10} (1.32 \cdot 1 0^{- 3})

- lo g_{10} (1.32) + 3

Decimal Notation

2.87942 \dots

Solution steps

- lo g_{10} (1.32 \cdot 1 0^{- 3})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (1.32 \cdot 1 0^{- 3}) = lo g_{10} (1.32) + lo g_{10} (1 0^{- 3})

= - (lo g_{10} (1.32) + lo g_{10} (1 0^{- 3}))

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (1 0^{- 3}) = - 3 lo g_{10} (10)

= - (lo g_{10} (1.32) - 3 lo g_{10} (10))

3 lo g_{10} (10) = 3

= - (lo g_{10} (1.32) - 3)

Distribute parentheses

= - (lo g_{10} (1.32)) - (- 3)

Apply minus-plus rules

- (- a) = a, - (a) = - a

= - lo g_{10} (1.32) + 3

lo g_{10} (10 a)

5 ln (x) - \frac{1}{5} ln (y)

- (\frac{2}{14}) lo g_{2} (\frac{2}{14}) - (\frac{3}{14}) lo g_{2} (\frac{3}{14})

lo g_{3} (\frac{9 x ^{4}}{y})

lo g_{m} (a b^{2} c^{3})

What is simplify-log_{10}(1.32*10^{-3}) ?
The solution to simplify-log_{10}(1.32*10^{-3}) is -log_{10}(1.32)+3