What is log_{a}(7x-4)-log_{a}(5x+2) ?

The solution to log_{a}(7x-4)-log_{a}(5x+2) is log_{a}((7x-4)/(5x+2))

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simplify log_{a}(7x-4)-log_{a}(5x+2)

simplify

lo g_{a} (7 x - 4) - lo g_{a} (5 x + 2)

lo g_{a} (\frac{7 x - 4}{5 x + 2})

Solution steps

lo g_{a} (7 x - 4) - lo g_{a} (5 x + 2)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{a} (7 x - 4) - lo g_{a} (5 x + 2) = lo g_{a} (\frac{7 x - 4}{5 x + 2})

= lo g_{a} (\frac{7 x - 4}{5 x + 2})

- lo g_{10} (1.6 \cdot 1 0^{- 5})

ln (\frac{e ^{8}}{15})

ln (x^{4} - 1) - ln (x^{2} - 1)

- lo g_{10} (4.1 \cdot 1 0^{- 2})

\frac{1}{2} lo g_{10} (m) + lo g_{10} (n)

What is log_{a}(7x-4)-log_{a}(5x+2) ?
The solution to log_{a}(7x-4)-log_{a}(5x+2) is log_{a}((7x-4)/(5x+2))