What are the solutions to the equation 3x^2+13x-30=0 ?

The solutions to the equation 3x^2+13x-30=0 are x= 5/3 ,x=-6

Find the zeros of 3x^2+13x-30=0

The zeros of 3x^2+13x-30=0 are x= 5/3 ,x=-6

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3 x^{2} + 13 x - 30 = 0

x = \frac{5}{3}, x = - 6

Solution steps

3 x^{2} + 13 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 3 ( - 30 )}{2 \cdot 3}

1 3^{2} - 4 \cdot 3 (- 30) = 23

x_{1, 2} = \frac{- 13 \pm 23}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 13 + 23}{2 \cdot 3}, x_{2} = \frac{- 13 - 23}{2 \cdot 3}

x = \frac{- 13 + 23}{2 \cdot 3} : \frac{5}{3}

x = \frac{- 13 - 23}{2 \cdot 3} : - 6

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - 6

\frac{( 5 - i )}{( 3 + 2 i )}

\frac{2 x ^{3} y ^{4} z ^{7}}{x ^{2} y ^{5} z ^{10}}

2 (b - 4) > - 6

1 + 4 (- 2 w + 1) \geq - 4 w + 2 + 6

6 a^{3} - 12 a^{2} + 14

What are the solutions to the equation 3x^2+13x-30=0 ?
The solutions to the equation 3x^2+13x-30=0 are x= 5/3 ,x=-6
Find the zeros of 3x^2+13x-30=0
The zeros of 3x^2+13x-30=0 are x= 5/3 ,x=-6