What is log_{8}(10)-log_{8}(2) ?

The solution to log_{8}(10)-log_{8}(2) is log_{8}(5)

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simplify log_{8}(10)-log_{8}(2)

simplify

lo g_{8} (10) - lo g_{8} (2)

lo g_{8} (5)

Decimal Notation

0.77397 \dots

Solution steps

lo g_{8} (10) - lo g_{8} (2)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{8} (10) - lo g_{8} (2) = lo g_{8} (\frac{10}{2})

= lo g_{8} (\frac{10}{2})

Divide the numbers:

\frac{10}{2} = 5

= lo g_{8} (5)

\frac{1}{4} lo g_{b} (x) + 4 lo g_{b} (y) - 3 lo g_{b} (x)

\frac{3}{2} ln x^{2} + x + \frac{1}{2} ln (8)

lo g_{3} (\frac{9}{x + 2})

lo g_{10} (2) 3

5 lo g_{10} (x) + 3 lo g_{10} (y) - 6 lo g_{10} (z)

What is log_{8}(10)-log_{8}(2) ?
The solution to log_{8}(10)-log_{8}(2) is log_{8}(5)