What is expand log_{3}(9(x^2-9)) ?

The solution to expand log_{3}(9(x^2-9)) is 2+log_{3}(x^2-9)

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expand log_{3}(9(x^2-9))

expand

lo g_{3} (9 (x^{2} - 9))

2 + lo g_{3} (x^{2} - 9)

Solution steps

lo g_{3} (9 (x^{2} - 9))

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{3} (9 (x^{2} - 9)) = lo g_{3} (9) + lo g_{3} (x^{2} - 9)

= lo g_{3} (9) + lo g_{3} (x^{2} - 9)

lo g_{3} (9) = 2

= 2 + lo g_{3} (x^{2} - 9)

lo g_{10} (\frac{a b ^{3}}{c ^{2}})

3 ln (\frac{1}{x})

ln (8 x^{3})

lo g_{2} (x) - lo g_{2} (x^{7})

- \frac{1}{6} lo g_{2} (\frac{1}{6}) - \frac{5}{6} lo g_{2} (\frac{5}{6})

What is expand log_{3}(9(x^2-9)) ?
The solution to expand log_{3}(9(x^2-9)) is 2+log_{3}(x^2-9)