What is expand log_{a}((x^8)/(yz^9)) ?

The solution to expand log_{a}((x^8)/(yz^9)) is 8log_{a}(x)-log_{a}(y)-9log_{a}(z)

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expand log_{a}((x^8)/(yz^9))

expand

lo g_{a} (\frac{x ^{8}}{y z ^{9}})

8 lo g_{a} (x) - lo g_{a} (y) - 9 lo g_{a} (z)

Solution steps

lo g_{a} (\frac{x ^{8}}{y z ^{9}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{a} (\frac{x ^{8}}{y z ^{9}}) = lo g_{a} (x^{8}) - lo g_{a} (y z^{9})

= lo g_{a} (x^{8}) - lo g_{a} (y z^{9})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{a} (x^{8}) = 8 lo g_{a} (x)

= 8 lo g_{a} (x) - lo g_{a} (y z^{9})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{a} (y z^{9}) = lo g_{a} (y) + lo g_{a} (z^{9})

= 8 lo g_{a} (x) - (lo g_{a} (y) + lo g_{a} (z^{9}))

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{a} (z^{9}) = 9 lo g_{a} (z)

= 8 lo g_{a} (x) - (lo g_{a} (y) + 9 lo g_{a} (z))

- (lo g_{a} (y) + 9 lo g_{a} (z)) : - lo g_{a} (y) - 9 lo g_{a} (z)

= 8 lo g_{a} (x) - lo g_{a} (y) - 9 lo g_{a} (z)

lo g_{2} (x + 5) - lo g_{2} (x - 2)

lo g_{6} (\frac{1}{6} m n^{2})

ln (\frac{e ^{2}}{10})

lo g_{a} (8) + lo g_{a} (5)

\frac{2 ln ( 2 )}{ln ( \frac{2}{3} )}

What is expand log_{a}((x^8)/(yz^9)) ?
The solution to expand log_{a}((x^8)/(yz^9)) is 8log_{a}(x)-log_{a}(y)-9log_{a}(z)