What is (log_{b}(x)-log_{b}(y))+4log_{b}(v) ?

The solution to (log_{b}(x)-log_{b}(y))+4log_{b}(v) is log_{b}((xv^4)/y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (log_{b}(x)-log_{b}(y))+4log_{b}(v)

simplify

(lo g_{b} (x) - lo g_{b} (y)) + 4 lo g_{b} (v)

lo g_{b} (\frac{x v ^{4}}{y})

Solution steps

(lo g_{b} (x) - lo g_{b} (y)) + 4 lo g_{b} (v)

Apply rule:

(a) = a

(lo g_{b} (x) - lo g_{b} (y)) = lo g_{b} (x) - lo g_{b} (y)

= lo g_{b} (x) - lo g_{b} (y) + 4 lo g_{b} (v)

Apply log rule:

b \cdot lo g_{a} (x) = lo g_{a} (x^{b})

4 lo g_{b} (v) = lo g_{b} (v^{4})

= lo g_{b} (x) - lo g_{b} (y) + lo g_{b} (v^{4})

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{b} (x) - lo g_{b} (y) = lo g_{b} (\frac{x}{y})

= lo g_{b} (\frac{x}{y}) + lo g_{b} (v^{4})

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{b} (\frac{x}{y}) + lo g_{b} (v^{4}) = lo g_{b} (\frac{x}{y} v^{4})

= lo g_{b} (\frac{x}{y} v^{4})

Simplify

\frac{x}{y} v^{4} : \frac{x v ^{4}}{y}

= lo g_{b} (\frac{x v ^{4}}{y})

lo g_{4} (\frac{16}{x + 5})

ln (\frac{535.6}{348.1})

lo g_{7} ((a + b) \cdot c)

ln (\frac{4 e ^{6}}{7 y})

ln (6 + x^{2}) - ln (7 + x)

What is (log_{b}(x)-log_{b}(y))+4log_{b}(v) ?
The solution to (log_{b}(x)-log_{b}(y))+4log_{b}(v) is log_{b}((xv^4)/y)