What is log_{5}(2)-2log_{5}(y) ?

The solution to log_{5}(2)-2log_{5}(y) is log_{5}(2/(y^2))

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simplify log_{5}(2)-2log_{5}(y)

simplify

lo g_{5} (2) - 2 lo g_{5} (y)

lo g_{5} (\frac{2}{y ^{2}})

Solution steps

lo g_{5} (2) - 2 lo g_{5} (y)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{5} (y) = lo g_{5} (y^{2})

= lo g_{5} (2) - lo g_{5} (y^{2})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{5} (2) - lo g_{5} (y^{2}) = lo g_{5} (\frac{2}{y ^{2}})

= lo g_{5} (\frac{2}{y ^{2}})

lo g_{2} (\frac{x}{a ^{2}})

3 lo g_{3} (5) - lo g_{3} (4)

\frac{7}{5} ln^{\frac{5}{7}} (\frac{1}{2})

ln (e (x - 6))

What is log_{5}(2)-2log_{5}(y) ?
The solution to log_{5}(2)-2log_{5}(y) is log_{5}(2/(y^2))