What is log_{6}((w^2)/v) ?

The solution to log_{6}((w^2)/v) is 2log_{6}(w)-log_{6}(v)

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simplify log_{6}((w^2)/v)

simplify

lo g_{6} (\frac{w ^{2}}{v})

2 lo g_{6} (w) - lo g_{6} (v)

Solution steps

lo g_{6} (\frac{w ^{2}}{v})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{6} (\frac{w ^{2}}{v}) = lo g_{6} (w^{2}) - lo g_{6} (v)

= lo g_{6} (w^{2}) - lo g_{6} (v)

Simplify

lo g_{6} (w^{2}) : 2 lo g_{6} (w)

= 2 lo g_{6} (w) - lo g_{6} (v)

ln (x^{2} 4 y)

lo g_{7} (\frac{x}{49})

2 lo g_{10} (4) - 3 lo g_{10} (3)

ln (x^{4} 2 - x)

ln (\frac{3 a ^{2} b ^{2}}{a})

What is log_{6}((w^2)/v) ?
The solution to log_{6}((w^2)/v) is 2log_{6}(w)-log_{6}(v)