What are the solutions to the equation 3p^2-5p-28=0 ?

The solutions to the equation 3p^2-5p-28=0 are p=4,p=-7/3

Find the zeros of 3p^2-5p-28=0

The zeros of 3p^2-5p-28=0 are p=4,p=-7/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 p^{2} - 5 p - 28 = 0

p = 4, p = - \frac{7}{3}

Decimal Notation

p = 4, p = - 2.33333 \dots

Solution steps

3 p^{2} - 5 p - 28 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 28 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 28) = 19

p_{1, 2} = \frac{- ( - 5 ) \pm 19}{2 \cdot 3}

Separate the solutions

p_{1} = \frac{- ( - 5 ) + 19}{2 \cdot 3}, p_{2} = \frac{- ( - 5 ) - 19}{2 \cdot 3}

p = \frac{- ( - 5 ) + 19}{2 \cdot 3} : 4

p = \frac{- ( - 5 ) - 19}{2 \cdot 3} : - \frac{7}{3}

The solutions to the quadratic equation are:

p = 4, p = - \frac{7}{3}

∣ x + 5 ∣ \leq = 10

p^{2} - 16

9 (\frac{1}{3})^{- 2}

∣ 2 x - 9 ∣ < 8

2 (3 x + 1) = - 3 (5 x - 5)

What are the solutions to the equation 3p^2-5p-28=0 ?
The solutions to the equation 3p^2-5p-28=0 are p=4,p=-7/3
Find the zeros of 3p^2-5p-28=0
The zeros of 3p^2-5p-28=0 are p=4,p=-7/3