What is log_{10}(7)-log_{10}(2) ?

The solution to log_{10}(7)-log_{10}(2) is log_{10}(7/2)

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simplify log_{10}(7)-log_{10}(2)

simplify

lo g_{10} (7) - lo g_{10} (2)

lo g_{10} (\frac{7}{2})

Decimal

0.54406 \dots

Solution steps

lo g_{10} (7) - lo g_{10} (2)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (7) - lo g_{10} (2) = lo g_{10} (\frac{7}{2})

= lo g_{10} (\frac{7}{2})

3 ln (2) + 2 ln (x) - \frac{1}{2} ln (x + 3)

lo g_{10} (7) - lo g_{10} (3)

ln (x^{4} sin^{2} (x))

lo g_{3} (2) + lo g_{3} (6)

lo g_{x} (+ 2 lo g_{y} (- 3 lo g_{a} (x)))

What is log_{10}(7)-log_{10}(2) ?
The solution to log_{10}(7)-log_{10}(2) is log_{10}(7/2)