What is expand log_{2}(y/(15)) ?

The solution to expand log_{2}(y/(15)) is log_{2}(y)-log_{2}(15)

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expand log_{2}(y/(15))

expand

lo g_{2} (\frac{y}{15})

lo g_{2} (y) - lo g_{2} (15)

Solution steps

lo g_{2} (\frac{y}{15})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{2} (\frac{y}{15}) = lo g_{2} (y) - lo g_{2} (15)

= lo g_{2} (y) - lo g_{2} (15)

lo g_{9} (5) - lo g_{9} (4)

3 ln (\frac{3}{2})

lo g_{3} (\frac{x}{4})

lo g_{3} (\frac{x}{9})

ln (\frac{1}{t})

What is expand log_{2}(y/(15)) ?
The solution to expand log_{2}(y/(15)) is log_{2}(y)-log_{2}(15)