What are the solutions to the equation 3x^2+2=-x ?

The solutions to the equation 3x^2+2=-x are x=-1/6+i(sqrt(23))/6 ,x=-1/6-i(sqrt(23))/6

Find the zeros of 3x^2+2=-x

The zeros of 3x^2+2=-x are x=-1/6+i(sqrt(23))/6 ,x=-1/6-i(sqrt(23))/6

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3 x^{2} + 2 = - x

x = - \frac{1}{6} + i \frac{23}{6}, x = - \frac{1}{6} - i \frac{23}{6}

Solution steps

3 x^{2} + 2 = - x

Move

x

to the left side

3 x^{2} + 2 + x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

Simplify

1^{2} - 4 \cdot 3 \cdot 2 : 23 i

x_{1, 2} = \frac{- 1 \pm 23 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 23 i}{2 \cdot 3}, x_{2} = \frac{- 1 - 23 i}{2 \cdot 3}

x = \frac{- 1 + 23 i}{2 \cdot 3} : - \frac{1}{6} + i \frac{23}{6}

x = \frac{- 1 - 23 i}{2 \cdot 3} : - \frac{1}{6} - i \frac{23}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{6} + i \frac{23}{6}, x = - \frac{1}{6} - i \frac{23}{6}

8 x^{2} - 6 x - 2 = 4

x^{2} - 2 x - 8

lo g_{\frac{1}{3}} (p) < 0

x + 1 = 7

x^{2} - 15 x - 100

What are the solutions to the equation 3x^2+2=-x ?
The solutions to the equation 3x^2+2=-x are x=-1/6+i(sqrt(23))/6 ,x=-1/6-i(sqrt(23))/6
Find the zeros of 3x^2+2=-x
The zeros of 3x^2+2=-x are x=-1/6+i(sqrt(23))/6 ,x=-1/6-i(sqrt(23))/6