What is log_{10}(a^2-b^2)-log_{10}(a+b) ?

The solution to log_{10}(a^2-b^2)-log_{10}(a+b) is log_{10}(a-b)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{10}(a^2-b^2)-log_{10}(a+b)

simplify

lo g_{10} (a^{2} - b^{2}) - lo g_{10} (a + b)

lo g_{10} (a - b)

Solution steps

lo g_{10} (a^{2} - b^{2}) - lo g_{10} (a + b)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (a^{2} - b^{2}) - lo g_{10} (a + b) = lo g_{10} (\frac{a ^{2} - b ^{2}}{a + b})

= lo g_{10} (\frac{a ^{2} - b ^{2}}{a + b})

Simplify

\frac{a ^{2} - b ^{2}}{a + b} : a - b

= lo g_{10} (a - b)

2.338 - 1.4995 - 0.287 \cdot ln (\frac{675}{45})

6 lo g_{4} (x) - 3 lo g_{4} (y)

lo g_{y} (3 ab c)

lo g_{10} (\frac{b ^{3}}{a})

What is log_{10}(a^2-b^2)-log_{10}(a+b) ?
The solution to log_{10}(a^2-b^2)-log_{10}(a+b) is log_{10}(a-b)