What is log_{2}(x^2)+log_{2}(x-1)-4 ?

The solution to log_{2}(x^2)+log_{2}(x-1)-4 is log_{2}(x^2(x-1))-4

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simplify log_{2}(x^2)+log_{2}(x-1)-4

simplify

lo g_{2} (x^{2}) + lo g_{2} (x - 1) - 4

lo g_{2} (x^{2} (x - 1)) - 4

Solution steps

lo g_{2} (x^{2}) + lo g_{2} (x - 1) - 4

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{2} (x^{2}) + lo g_{2} (x - 1) = lo g_{2} (x^{2} (x - 1))

= lo g_{2} (x^{2} (x - 1)) - 4

(- \frac{6}{10}) lo g_{2} (\frac{6}{10}) - (\frac{4}{10}) lo g_{2} (\frac{4}{10})

- (\frac{2}{6}) lo g_{2} (\frac{2}{6}) - (\frac{4}{6}) lo g_{2} (\frac{4}{6})

lo g_{10} (x) - 5 lo g_{10} (y) + 8 lo g_{10} (z)

lo g_{7} (6) + lo g_{7} (3) - lo g_{7} (2)

- 7 ln (x) - 8 ln (y) - 3 ln (z)

What is log_{2}(x^2)+log_{2}(x-1)-4 ?
The solution to log_{2}(x^2)+log_{2}(x-1)-4 is log_{2}(x^2(x-1))-4