What is log_{b}(1/10)+log_{b}(30) ?

The solution to log_{b}(1/10)+log_{b}(30) is log_{b}(3)

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simplify log_{b}(1/10)+log_{b}(30)

simplify

lo g_{b} (\frac{1}{10}) + lo g_{b} (30)

lo g_{b} (3)

Solution steps

lo g_{b} (\frac{1}{10}) + lo g_{b} (30)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{b} (\frac{1}{10}) + lo g_{b} (30) = lo g_{b} (\frac{1}{10} \cdot 30)

= lo g_{b} (\frac{1}{10} \cdot 30)

\frac{1}{10} \cdot 30 = 3

= lo g_{b} (3)

2.715096 - 1.70203 - 0.287 ln (\frac{3000}{110})

lo g_{3} (u) - 5 lo g_{3} (v)

lo g_{2} (7) - 7 lo g_{2} (x) + \frac{1}{2} lo g_{2} (x + 1)

lo g_{2} (7 x y)

ln (\frac{33}{58})

What is log_{b}(1/10)+log_{b}(30) ?
The solution to log_{b}(1/10)+log_{b}(30) is log_{b}(3)