What is log_{10}((y^9)/(sqrt(2x))) ?

The solution to log_{10}((y^9)/(sqrt(2x))) is 9log_{10}(y)-log_{10}(sqrt(2x))

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simplify log_{10}((y^9)/(sqrt(2x)))

simplify

lo g_{10} (\frac{y ^{9}}{2 x})

9 lo g_{10} (y) - lo g_{10} (2 x)

Solution steps

lo g_{10} (\frac{y ^{9}}{2 x})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{y ^{9}}{2 x}) = lo g_{10} (y^{9}) - lo g_{10} (2 x)

= lo g_{10} (y^{9}) - lo g_{10} (2 x)

Simplify

lo g_{10} (y^{9}) : 9 lo g_{10} (y)

= 9 lo g_{10} (y) - lo g_{10} (2 x)

ln (\frac{7}{5 x ^{5} y})

3 lo g_{10} (x + 1) + lo g_{10} (4 x + 7)

lo g_{10} (\frac{7 a}{8})

lo g_{3} (1 2^{\frac{5}{6}}) x^{9}

lo g_{5} (\frac{x}{125})

What is log_{10}((y^9)/(sqrt(2x))) ?
The solution to log_{10}((y^9)/(sqrt(2x))) is 9log_{10}(y)-log_{10}(sqrt(2x))