What is log_{10}((64)/z) ?

The solution to log_{10}((64)/z) is 6log_{10}(2)-log_{10}(z)

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simplify log_{10}((64)/z)

simplify

lo g_{10} (\frac{64}{z})

6 lo g_{10} (2) - lo g_{10} (z)

Solution steps

lo g_{10} (\frac{64}{z})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{64}{z}) = lo g_{10} (64) - lo g_{10} (z)

= lo g_{10} (64) - lo g_{10} (z)

lo g_{10} (64) = 6 lo g_{10} (2)

= 6 lo g_{10} (2) - lo g_{10} (z)

\frac{1}{3} lo g_{4} (x) + lo g_{4} (y) - 2

2 lo g_{10} (2 x)

ln (x yz)

lo g_{\frac{3}{2}} (x) + lo g_{x} (\frac{2}{3})

lo g_{4} (\frac{g}{64})

What is log_{10}((64)/z) ?
The solution to log_{10}((64)/z) is 6log_{10}(2)-log_{10}(z)