What is 2log_{3}(3x-5)-log_{3}(1-6x) ?

The solution to 2log_{3}(3x-5)-log_{3}(1-6x) is log_{3}(((3x-5)^2)/(1-6x))

Popular >

simplify 2log_{3}(3x-5)-log_{3}(1-6x)

simplify

2 lo g_{3} (3 x - 5) - lo g_{3} (1 - 6 x)

lo g_{3} (\frac{( 3 x - 5 ) ^{2}}{1 - 6 x})

Solution steps

2 lo g_{3} (3 x - 5) - lo g_{3} (1 - 6 x)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{3} (3 x - 5) = lo g_{3} ((3 x - 5)^{2})

= lo g_{3} ((3 x - 5)^{2}) - lo g_{3} (- 6 x + 1)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{3} ((3 x - 5)^{2}) - lo g_{3} (1 - 6 x) = lo g_{3} (\frac{( 3 x - 5 ) ^{2}}{- 6 x + 1})

= lo g_{3} (\frac{( 3 x - 5 ) ^{2}}{1 - 6 x})

ln (7 e + 14) - ln (7) - ln (e + 2)

0.5 ln (16 x^{2})

16.7 + 10 lo g_{10} (\frac{750}{100})

20 ln (\frac{1400}{1400 + ( 10 ( 10 ) )}) + (9.8 \cdot 10)

What is 2log_{3}(3x-5)-log_{3}(1-6x) ?
The solution to 2log_{3}(3x-5)-log_{3}(1-6x) is log_{3}(((3x-5)^2)/(1-6x))