What is log_{3}(1/4+1)-log_{3}(1/4) ?

The solution to log_{3}(1/4+1)-log_{3}(1/4) is log_{3}(5)

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simplify log_{3}(1/4+1)-log_{3}(1/4)

simplify

lo g_{3} (\frac{1}{4} + 1) - lo g_{3} (\frac{1}{4})

lo g_{3} (5)

Decimal Notation

1.46497 \dots

Solution steps

lo g_{3} (\frac{1}{4} + 1) - lo g_{3} (\frac{1}{4})

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{3} (\frac{1}{4} + 1) - lo g_{3} (\frac{1}{4}) = lo g_{3} (\frac{\frac{1}{4} + 1}{\frac{1}{4}})

= lo g_{3} (\frac{\frac{1}{4} + 1}{\frac{1}{4}})

\frac{\frac{1}{4} + 1}{\frac{1}{4}} = 5

= lo g_{3} (5)

\frac{1}{2} lo g_{9} (x) + lo g_{9} (y)

ln (\frac{98}{45})

2 ln (x) - \frac{1}{5} ln (y)

lo g_{7} (2 x)

lo g_{b} (x + 1) + lo g_{b} (3) - lo g_{b} (x + 2)

What is log_{3}(1/4+1)-log_{3}(1/4) ?
The solution to log_{3}(1/4+1)-log_{3}(1/4) is log_{3}(5)