What is expand log_{4}((16)/(sqrt(x+9))) ?

The solution to expand log_{4}((16)/(sqrt(x+9))) is 2-log_{4}(sqrt(x+9))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand log_{4}((16)/(sqrt(x+9)))

expand

lo g_{4} (\frac{16}{x + 9})

2 - lo g_{4} (x + 9)

Solution steps

lo g_{4} (\frac{16}{x + 9})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{4} (\frac{16}{x + 9}) = lo g_{4} (16) - lo g_{4} (x + 9)

= lo g_{4} (16) - lo g_{4} (x + 9)

lo g_{4} (16) = 2

= 2 - lo g_{4} (x + 9)

ln (\frac{x ^{2} - 1}{x ^{3}})

4 lo g_{2} (u) + 7 lo g_{2} (v)

\frac{1}{2} lo g_{c} (x) + 2 lo g_{c} (y) - 3 lo g_{c} (x)

- lo g_{10} (1.9 \cdot 1 0^{- 6})

lo g_{3} (x^{2} - 25) - lo g_{3} (x - 5)

What is expand log_{4}((16)/(sqrt(x+9))) ?
The solution to expand log_{4}((16)/(sqrt(x+9))) is 2-log_{4}(sqrt(x+9))