What is log_{10}(40)-log_{10}(8) ?

The solution to log_{10}(40)-log_{10}(8) is log_{10}(5)

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simplify log_{10}(40)-log_{10}(8)

simplify

lo g_{10} (40) - lo g_{10} (8)

lo g_{10} (5)

Decimal Notation

0.69897 \dots

Solution steps

lo g_{10} (40) - lo g_{10} (8)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (40) - lo g_{10} (8) = lo g_{10} (\frac{40}{8})

= lo g_{10} (\frac{40}{8})

Divide the numbers:

\frac{40}{8} = 5

= lo g_{10} (5)

lo g_{3} (x) + 3 lo g_{3} (a + 2) - lo g_{3} (a + 7)

lo g_{2} (2) + lo g_{2} (x) + 2 lo g_{2} (y)

lo g_{10} (3) - lo g_{10} (5)

lo g_{6} (\frac{x ^{2}}{5 y})

7 lo g_{6} (u) + 4 lo g_{6} (v)

What is log_{10}(40)-log_{10}(8) ?
The solution to log_{10}(40)-log_{10}(8) is log_{10}(5)