What is log_{10}(296)-log_{10}(23) ?

The solution to log_{10}(296)-log_{10}(23) is log_{10}(296/23)

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simplify log_{10}(296)-log_{10}(23)

simplify

lo g_{10} (296) - lo g_{10} (23)

lo g_{10} (\frac{296}{23})

Decimal Notation

1.10956 \dots

Solution steps

lo g_{10} (296) - lo g_{10} (23)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (296) - lo g_{10} (23) = lo g_{10} (\frac{296}{23})

= lo g_{10} (\frac{296}{23})

2 lo g_{5} (x) + \frac{1}{2} lo g_{5} (y) - 4 lo g_{5} (x)

lo g_{4} (\frac{16}{x + 9})

lo g_{10} (\frac{x ^{2} + y ^{2}}{( x - y ) ^{3}})

ln (\frac{- 4.15 + 8.05}{31.8})

- (\frac{17}{30}) lo g_{2} (\frac{17}{30}) - (\frac{13}{30}) lo g_{2} (\frac{13}{30})

What is log_{10}(296)-log_{10}(23) ?
The solution to log_{10}(296)-log_{10}(23) is log_{10}(296/23)