What is log_{9}((\sqrt[4]{7})/(s^2r)) ?

The solution to log_{9}((\sqrt[4]{7})/(s^2r)) is log_{9}(\sqrt[4]{7})-log_{3}(s)-log_{9}(r)

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simplify log_{9}((\sqrt[4]{7})/(s^2r))

simplify

Solution steps

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

Simplify

lo g_{9} (s^{2} r) : lo g_{3} (s) + lo g_{9} (r)

Apply the distributive law:

- (a + b) = - a - b

- (lo g_{3} (s) + lo g_{9} (r)) = - lo g_{3} (s) - lo g_{9} (r)

lo g_{3} (\frac{1}{16}) - 1

lo g_{10} (\frac{x}{2})

ln (\frac{x ^{3}}{x ( 1 + x ) ^{2}})

lo g_{10} (125) - lo g_{10} (\frac{45}{27})

lo g_{10} (\frac{x}{10000 y ^{4}})

What is log_{9}((\sqrt[4]{7})/(s^2r)) ?
The solution to log_{9}((\sqrt[4]{7})/(s^2r)) is log_{9}(\sqrt[4]{7})-log_{3}(s)-log_{9}(r)