What is log_{10}(A)-log_{10}(B) ?

The solution to log_{10}(A)-log_{10}(B) is log_{10}(A/B)

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simplify log_{10}(A)-log_{10}(B)

simplify

lo g_{10} (A) - lo g_{10} (B)

lo g_{10} (\frac{A}{B})

Solution steps

lo g_{10} (A) - lo g_{10} (B)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (A) - lo g_{10} (B) = lo g_{10} (\frac{A}{B})

= lo g_{10} (\frac{A}{B})

lo g_{10} (\frac{x ^{2} ( 1 + x ^{2} ) ^{2}}{( 1 - x ^{2} ) ^{2}})

lo g_{6} ((\frac{z}{36})^{4})

\frac{1}{2} lo g_{10} (16 x^{4}) + lo g_{10} (2 x)

lo g_{a} (26) + lo g_{a} (4)

lo g_{10} (\frac{x ^{3} y}{z ^{2}})

What is log_{10}(A)-log_{10}(B) ?
The solution to log_{10}(A)-log_{10}(B) is log_{10}(A/B)