What is ln(b^2*\sqrt[6]{a}) ?

The solution to ln(b^2*\sqrt[6]{a}) is 2ln(b)+ln(\sqrt[6]{a})

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simplify ln(b^2*\sqrt[6]{a})

simplify

Solution steps

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (b^{2}) = 2 ln (b)

- lo g_{10} (3.1 \cdot 1 0^{- 6})

\frac{ln ( 3 )}{2 ln ( 2 ) - ln ( 3 )}

lo g_{4} (\frac{1}{4} x^{2})

- \frac{1}{3} ln (2)

lo g_{2} (\frac{x}{8})

What is ln(b^2*\sqrt[6]{a}) ?
The solution to ln(b^2*\sqrt[6]{a}) is 2ln(b)+ln(\sqrt[6]{a})