What is the answer to 2.25=(5-2b)/4 (1)^2+b^1 ?

The answer to 2.25=(5-2b)/4 (1)^2+b^1 is b=2

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2.25=(5-2b)/4 (1)^2+b^1

2.25 = \frac{5 - 2 b}{4} (1)^{2} + b^{1}

b = 2

Solution steps

2.25 = \frac{5 - 2 b}{4} (1)^{2} + b^{1}

Switch sides

\frac{5 - 2 b}{4} (1)^{2} + b^{1} = 2.25

Apply rule

1^{a} = 1

1^{2} = 1

1 \cdot \frac{- 2 b + 5}{4} + b^{1} = 2.25

Apply rule

a^{1} = a

b^{1} = b

1 \cdot \frac{- 2 b + 5}{4} + b = 2.25

Multiply:

\frac{5 - 2 b}{4} \cdot 1 = \frac{5 - 2 b}{4}

\frac{5 - 2 b}{4} + b = 2.25

Multiply both sides by

4

5 + 2 b = 9

Move

5

to the right side

2 b = 4

Divide both sides by

2

b = 2

lo g_{2} (128) = x

- \frac{5}{6} - \frac{2}{3}

3 x - 26 = 10

\frac{k}{k - n} - \frac{k}{n - k}

2 - 12

What is the answer to 2.25=(5-2b)/4 (1)^2+b^1 ?
The answer to 2.25=(5-2b)/4 (1)^2+b^1 is b=2
Solve for b: 2.25=(5-2b)/4 (1)^2+b^1
The solution is b=2