What is log_{6}(11)-log_{6}(z) ?

The solution to log_{6}(11)-log_{6}(z) is log_{6}((11)/z)

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simplify log_{6}(11)-log_{6}(z)

simplify

lo g_{6} (11) - lo g_{6} (z)

lo g_{6} (\frac{11}{z})

Solution steps

lo g_{6} (11) - lo g_{6} (z)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{6} (11) - lo g_{6} (z) = lo g_{6} (\frac{11}{z})

= lo g_{6} (\frac{11}{z})

lo g_{9} (\frac{3 a}{7})

\frac{ln ( \frac{5}{3} )}{ln ( 3 ) - ln ( 5 )}

- 2 ln (3) + 3 ln (4) + 3 ln (2)

lo g_{a} (\frac{3}{2})

lo g_{10} (y^{6} z)

What is log_{6}(11)-log_{6}(z) ?
The solution to log_{6}(11)-log_{6}(z) is log_{6}((11)/z)