What is log_{2}((x^2)/(x+1)) ?

The solution to log_{2}((x^2)/(x+1)) is 2log_{2}(x)-log_{2}(x+1)

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simplify log_{2}((x^2)/(x+1))

simplify

lo g_{2} (\frac{x ^{2}}{x + 1})

2 lo g_{2} (x) - lo g_{2} (x + 1)

Solution steps

lo g_{2} (\frac{x ^{2}}{x + 1})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{2} (\frac{x ^{2}}{x + 1}) = lo g_{2} (x^{2}) - lo g_{2} (x + 1)

= lo g_{2} (x^{2}) - lo g_{2} (x + 1)

Simplify

lo g_{2} (x^{2}) : 2 lo g_{2} (x)

= 2 lo g_{2} (x) - lo g_{2} (x + 1)

lo g_{10} (\frac{x}{7})

4 (- ln (e^{3} z^{\frac{5}{2}}) + ln (\frac{x ^{3}}{y ^{2}}))

\frac{12 ln ( 3 )}{ln ( 20 )} - 1

ln (\frac{ψ}{2 ^{ψ}} \cdot (2 - x)^{ψ - 1})

ln (y \frac{y}{2 - y})

What is log_{2}((x^2)/(x+1)) ?
The solution to log_{2}((x^2)/(x+1)) is 2log_{2}(x)-log_{2}(x+1)