What is log_{4}(8)+log_{4}(6) ?

The solution to log_{4}(8)+log_{4}(6) is log_{4}(48)

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simplify log_{4}(8)+log_{4}(6)

simplify

lo g_{4} (8) + lo g_{4} (6)

lo g_{4} (48)

Decimal Notation

2.79248 \dots

Solution steps

lo g_{4} (8) + lo g_{4} (6)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{4} (8) + lo g_{4} (6) = lo g_{4} (8 \cdot 6)

= lo g_{4} (8 \cdot 6)

Multiply the numbers:

8 \cdot 6 = 48

= lo g_{4} (48)

lo g_{4} (\frac{1}{16} t^{3} v)

lo g_{10} (3) + 2 lo g_{10} (4)

ln (3 x) - ln (3)

ln (4 \cdot 1 0^{14})

ln (7 e^{3})

What is log_{4}(8)+log_{4}(6) ?
The solution to log_{4}(8)+log_{4}(6) is log_{4}(48)