What is log_{2}(4)+log_{2}(6)+log_{2}(3) ?

The solution to log_{2}(4)+log_{2}(6)+log_{2}(3) is log_{2}(72)

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simplify log_{2}(4)+log_{2}(6)+log_{2}(3)

simplify

lo g_{2} (4) + lo g_{2} (6) + lo g_{2} (3)

lo g_{2} (72)

Decimal Notation

6.16992 \dots

Solution steps

lo g_{2} (4) + lo g_{2} (6) + lo g_{2} (3)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{2} (4) + lo g_{2} (6) = lo g_{2} (4 \cdot 6)

= lo g_{2} (4 \cdot 6) + lo g_{2} (3)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{2} (4 \cdot 6) + lo g_{2} (3) = lo g_{2} (4 \cdot 6 \cdot 3)

= lo g_{2} (4 \cdot 6 \cdot 3)

Multiply the numbers:

4 \cdot 6 \cdot 3 = 72

= lo g_{2} (72)

lo g_{3} (3 x)

ln (\frac{x ^{4} y}{z ^{5}})

lo g_{5} (\frac{125}{x + 3})

lo g_{b} (y^{6} x)

2 ln (2) - \frac{1}{2} ln (x^{3} + 4 x)

What is log_{2}(4)+log_{2}(6)+log_{2}(3) ?
The solution to log_{2}(4)+log_{2}(6)+log_{2}(3) is log_{2}(72)