What are the solutions to the equation 4x^2+8x-17=x^2-2x ?

The solutions to the equation 4x^2+8x-17=x^2-2x are x=(-5+2sqrt(19))/3 ,x=-(5+2sqrt(19))/3

Find the zeros of 4x^2+8x-17=x^2-2x

The zeros of 4x^2+8x-17=x^2-2x are x=(-5+2sqrt(19))/3 ,x=-(5+2sqrt(19))/3

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4 x^{2} + 8 x - 17 = x^{2} - 2 x

x = \frac{- 5 + 2 19}{3}, x = - \frac{5 + 2 19}{3}

Solution steps

4 x^{2} + 8 x - 17 = x^{2} - 2 x

Move

2 x

to the left side

4 x^{2} + 10 x - 17 = x^{2}

Move

x^{2}

to the left side

3 x^{2} + 10 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 17 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 17) = 419

x_{1, 2} = \frac{- 10 \pm 4 19}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 4 19}{2 \cdot 3}, x_{2} = \frac{- 10 - 4 19}{2 \cdot 3}

x = \frac{- 10 + 4 19}{2 \cdot 3} : \frac{- 5 + 2 19}{3}

x = \frac{- 10 - 4 19}{2 \cdot 3} : - \frac{5 + 2 19}{3}

The solutions to the quadratic equation are:

x = \frac{- 5 + 2 19}{3}, x = - \frac{5 + 2 19}{3}

\frac{9}{9 ^{- \frac{4}{5}}}

\frac{3}{2} \cdot 9

3 x^{2} - 36 x = 0

\frac{4}{3 x - 2} \leq \frac{2}{x + 1}

4 x - 4 = - 40

What are the solutions to the equation 4x^2+8x-17=x^2-2x ?
The solutions to the equation 4x^2+8x-17=x^2-2x are x=(-5+2sqrt(19))/3 ,x=-(5+2sqrt(19))/3
Find the zeros of 4x^2+8x-17=x^2-2x
The zeros of 4x^2+8x-17=x^2-2x are x=(-5+2sqrt(19))/3 ,x=-(5+2sqrt(19))/3