What is log_{10}((sqrt(bc))/a) ?

The solution to log_{10}((sqrt(bc))/a) is log_{10}(sqrt(bc))-log_{10}(a)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{10}((sqrt(bc))/a)

simplify

lo g_{10} (\frac{b c}{a})

lo g_{10} (b c) - lo g_{10} (a)

Solution steps

lo g_{10} (\frac{b c}{a})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{b c}{a}) = lo g_{10} (b c) - lo g_{10} (a)

= lo g_{10} (b c) - lo g_{10} (a)

lo g_{2} (4 x y^{5})

lo g_{10} (p^{x} (1 - p)^{n - x})

5 lo g_{2} (x) - 9 lo g_{2} (y)

ln (\frac{5 x - 1}{x + 6})

lo g_{4} (x^{3}) y^{5}

What is log_{10}((sqrt(bc))/a) ?
The solution to log_{10}((sqrt(bc))/a) is log_{10}(sqrt(bc))-log_{10}(a)