What is log_{10}(2.3)-log_{10}(3.1) ?

The solution to log_{10}(2.3)-log_{10}(3.1) is log_{10}(23/31)

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simplify log_{10}(2.3)-log_{10}(3.1)

simplify

lo g_{10} (2.3) - lo g_{10} (3.1)

lo g_{10} (\frac{23}{31})

Decimal Notation

- 0.12963 \dots

Solution steps

lo g_{10} (2.3) - lo g_{10} (3.1)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (2.3) - lo g_{10} (3.1) = lo g_{10} (\frac{2.3}{3.1})

= lo g_{10} (\frac{2.3}{3.1})

\frac{2.3}{3.1} = \frac{23}{31}

= lo g_{10} (\frac{23}{31})

lo g_{4} (x) + lo g_{4} (x - 3)

lo g_{10} (x) - 3 lo g_{10} (y) + 5 lo g_{10} (z)

3 lo g_{10} (x) - 5 lo g_{10} (y)

lo g_{b} (\frac{p ^{2} q ^{5}}{m ^{5} b ^{7}})

lo g_{5} (11) - lo g_{5} (9)

What is log_{10}(2.3)-log_{10}(3.1) ?
The solution to log_{10}(2.3)-log_{10}(3.1) is log_{10}(23/31)