What is 4-(3+1)^2-6\div 2+4 ?

The solution to 4-(3+1)^2-6\div 2+4 is -11

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4-(3+1)^2-6\div 2+4

4 - (3 + 1)^{2} - 6 \div 2 + 4

- 11

Solution steps

4 - (3 + 1)^{2} - 6 \div 2 + 4

Follow the PEMDAS order of operations

Calculate within parentheses

(3 + 1) : 4

= 4 - 4^{2} - 6 \div 2 + 4

Calculate exponents

4^{2} : 16

= 4 - 16 - 6 \div 2 + 4

Multiply and divide (left to right)

6 \div 2 : 3

= 4 - 16 - 3 + 4

Add and subtract (left to right)

4 - 16 - 3 + 4 : - 11

= - 11

\frac{ln ( 25 )}{0.125} = t

\frac{3}{5} + \frac{3}{8}

14 \cdot 8

4 x + 1 > 17

\frac{4}{5} - 2 x + \frac{3 x}{2} = \frac{3}{4} - \frac{7 x}{10}