What is log_{10}(5)+log_{10}(6)-log_{10}(2) ?

The solution to log_{10}(5)+log_{10}(6)-log_{10}(2) is log_{10}(15)

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simplify log_{10}(5)+log_{10}(6)-log_{10}(2)

simplify

lo g_{10} (5) + lo g_{10} (6) - lo g_{10} (2)

lo g_{10} (15)

Decimal Notation

1.17609 \dots

Solution steps

lo g_{10} (5) + lo g_{10} (6) - lo g_{10} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (5) + lo g_{10} (6) = lo g_{10} (5 \cdot 6)

= lo g_{10} (5 \cdot 6) - lo g_{10} (2)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (5 \cdot 6) - lo g_{10} (2) = lo g_{10} (\frac{5 \cdot 6}{2})

= lo g_{10} (\frac{5 \cdot 6}{2})

Cancel

\frac{5 \cdot 6}{2} : 15

= lo g_{10} (15)

4 ln (x + \frac{6}{4}) + ln (x + 1)

ln (10 x) - ln (z)

lo g_{9} ((x y^{3})^{3})

What is log_{10}(5)+log_{10}(6)-log_{10}(2) ?
The solution to log_{10}(5)+log_{10}(6)-log_{10}(2) is log_{10}(15)