What are the solutions to the equation 2x^2=5x+12 ?

The solutions to the equation 2x^2=5x+12 are x=4,x=-3/2

Find the zeros of 2x^2=5x+12

The zeros of 2x^2=5x+12 are x=4,x=-3/2

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2 x^{2} = 5 x + 12

x = 4, x = - \frac{3}{2}

Solution steps

2 x^{2} = 5 x + 12

Move

12

to the left side

2 x^{2} - 12 = 5 x

Move

5 x

to the left side

2 x^{2} - 12 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 12) = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 2}

x = \frac{- ( - 5 ) + 11}{2 \cdot 2} : 4

x = \frac{- ( - 5 ) - 11}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 4, x = - \frac{3}{2}

5 (- 3 + 3 x) = 4 x - 26

\frac{t}{y - t} - \frac{y}{y + t}

(i 2 - 1) (2 i 2 + 3)

∣ - 2 x ∣ = 4

\frac{x ^{2}}{x ^{- 2}}

What are the solutions to the equation 2x^2=5x+12 ?
The solutions to the equation 2x^2=5x+12 are x=4,x=-3/2
Find the zeros of 2x^2=5x+12
The zeros of 2x^2=5x+12 are x=4,x=-3/2