What is log_{7}(2)+log_{7}(a+4b) ?

The solution to log_{7}(2)+log_{7}(a+4b) is log_{7}(2(a+4b))

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simplify log_{7}(2)+log_{7}(a+4b)

simplify

lo g_{7} (2) + lo g_{7} (a + 4 b)

lo g_{7} (2 (a + 4 b))

Solution steps

lo g_{7} (2) + lo g_{7} (a + 4 b)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{7} (2) + lo g_{7} (a + 4 b) = lo g_{7} (2 (a + 4 b))

= lo g_{7} (2 (a + 4 b))

4 lo g_{b} (x) + 2 lo g_{b} (z)

ln ((e^{x} e^{2})^{3})

\frac{1}{2} ln (ab)

lo g_{a} (\frac{x y ^{\frac{3}{5}}}{z ^{4}})

What is log_{7}(2)+log_{7}(a+4b) ?
The solution to log_{7}(2)+log_{7}(a+4b) is log_{7}(2(a+4b))