What is log_{b}(7)+log_{b}(3) ?

The solution to log_{b}(7)+log_{b}(3) is log_{b}(21)

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simplify log_{b}(7)+log_{b}(3)

simplify

lo g_{b} (7) + lo g_{b} (3)

lo g_{b} (21)

Solution steps

lo g_{b} (7) + lo g_{b} (3)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{b} (7) + lo g_{b} (3) = lo g_{b} (7 \cdot 3)

= lo g_{b} (7 \cdot 3)

Multiply the numbers:

7 \cdot 3 = 21

= lo g_{b} (21)

\frac{ln ( 12 ) - ln ( 2 )}{10}

5 lo g_{10} (6) - 3 lo g_{10} (x)

ln (x) - ln (- x)

2 lo g_{3} (x) + 4 lo g_{3} (y)

ln (\frac{ln ( x )}{x - 1})

What is log_{b}(7)+log_{b}(3) ?
The solution to log_{b}(7)+log_{b}(3) is log_{b}(21)