What is log_{5}(2)-log_{5}(x)-log_{5}(y) ?

The solution to log_{5}(2)-log_{5}(x)-log_{5}(y) is log_{5}(2/(xy))

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simplify log_{5}(2)-log_{5}(x)-log_{5}(y)

simplify

lo g_{5} (2) - lo g_{5} (x) - lo g_{5} (y)

lo g_{5} (\frac{2}{x y})

Solution steps

lo g_{5} (2) - lo g_{5} (x) - lo g_{5} (y)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{5} (2) - lo g_{5} (x) = lo g_{5} (\frac{2}{x})

= lo g_{5} (\frac{2}{x}) - lo g_{5} (y)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{5} (\frac{2}{x}) - lo g_{5} (y) = lo g_{5} (\frac{\frac{2}{x}}{y})

= lo g_{5} (\frac{\frac{2}{x}}{y})

Simplify

\frac{\frac{2}{x}}{y} : \frac{2}{x y}

= lo g_{5} (\frac{2}{x y})

\frac{1}{3} (lo g_{2} (c) + lo g_{2} (d)) - 4 lo g_{2} (e)

lo g_{w} (\frac{9 x}{5})

lo g_{10} (x \cdot y \cdot z^{5})

(lo g_{c} (x) - lo g_{c} (y)) + 5 lo g_{c} (v)

1 + lo g_{10} (a) - \frac{1}{2} lo g_{10} (b)

What is log_{5}(2)-log_{5}(x)-log_{5}(y) ?
The solution to log_{5}(2)-log_{5}(x)-log_{5}(y) is log_{5}(2/(xy))