What is log_{10}((ab^2)/m) ?

The solution to log_{10}((ab^2)/m) is log_{10}(a)+2log_{10}(b)-log_{10}(m)

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simplify log_{10}((ab^2)/m)

simplify

lo g_{10} (\frac{a b ^{2}}{m})

lo g_{10} (a) + 2 lo g_{10} (b) - lo g_{10} (m)

Solution steps

lo g_{10} (\frac{a b ^{2}}{m})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{a b ^{2}}{m}) = lo g_{10} (a b^{2}) - lo g_{10} (m)

= lo g_{10} (a b^{2}) - lo g_{10} (m)

Simplify

lo g_{10} (a b^{2}) : lo g_{10} (a) + 2 lo g_{10} (b)

= lo g_{10} (a) + 2 lo g_{10} (b) - lo g_{10} (m)

- ln (\frac{y}{x}) - ln (x)

2 lo g_{10} (c) + 4 lo g_{10} (k)

lo g_{5} ((x + y) \cdot z)

213 - \frac{3}{2} ln (4 + 13) - 1 + \frac{3}{2} ln (3)

ln (\frac{4 0 ^{2}}{1 0 ^{2}})

What is log_{10}((ab^2)/m) ?
The solution to log_{10}((ab^2)/m) is log_{10}(a)+2log_{10}(b)-log_{10}(m)