What are the solutions to the equation x^2+3x-6=0 ?

The solutions to the equation x^2+3x-6=0 are x=(-3+sqrt(33))/2 ,x=(-3-sqrt(33))/2

Find the zeros of x^2+3x-6=0

The zeros of x^2+3x-6=0 are x=(-3+sqrt(33))/2 ,x=(-3-sqrt(33))/2

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x^{2} + 3 x - 6 = 0

x = \frac{- 3 + 33}{2}, x = \frac{- 3 - 33}{2}

Solution steps

x^{2} + 3 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 6) = 33

x_{1, 2} = \frac{- 3 \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 33}{2 \cdot 1}, x_{2} = \frac{- 3 - 33}{2 \cdot 1}

x = \frac{- 3 + 33}{2 \cdot 1} : \frac{- 3 + 33}{2}

x = \frac{- 3 - 33}{2 \cdot 1} : \frac{- 3 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 33}{2}, x = \frac{- 3 - 33}{2}

4 = \frac{x}{- 4} + 8

12 (x - 1) = 8 (x + 1)

(- 1)^{- \frac{1}{2}}

(5.972 \cdot 1 0^{24}) (3.83 \cdot 1 0^{5} - x)^{2} = x^{2} \cdot (7.35 \cdot 1 0^{22})

\frac{1}{2} x^{- 2}

What are the solutions to the equation x^2+3x-6=0 ?
The solutions to the equation x^2+3x-6=0 are x=(-3+sqrt(33))/2 ,x=(-3-sqrt(33))/2
Find the zeros of x^2+3x-6=0
The zeros of x^2+3x-6=0 are x=(-3+sqrt(33))/2 ,x=(-3-sqrt(33))/2