What is log_{2}((7y)/z) ?

The solution to log_{2}((7y)/z) is log_{2}(7)+log_{2}(y)-log_{2}(z)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{2}((7y)/z)

simplify

lo g_{2} (\frac{7 y}{z})

lo g_{2} (7) + lo g_{2} (y) - lo g_{2} (z)

Solution steps

lo g_{2} (\frac{7 y}{z})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{2} (\frac{7 y}{z}) = lo g_{2} (7 y) - lo g_{2} (z)

= lo g_{2} (7 y) - lo g_{2} (z)

Simplify

lo g_{2} (7 y) : lo g_{2} (7) + lo g_{2} (y)

= lo g_{2} (7) + lo g_{2} (y) - lo g_{2} (z)

3 lo g_{10} (x) + 5 lo g_{10} (y)

lo g_{f} (\frac{s t ^{8}}{r ^{5}})

lo g_{5} ((x + 10) (x - 10))

2 [lo g_{3} (20) - lo g_{3} (4)] + \frac{1}{2} lo g_{3} (4)

What is log_{2}((7y)/z) ?
The solution to log_{2}((7y)/z) is log_{2}(7)+log_{2}(y)-log_{2}(z)