What is expand log_{10}((sqrt(x))/(2y^2)) ?

The solution to expand log_{10}((sqrt(x))/(2y^2)) is log_{10}(sqrt(x))-log_{10}(2)-2log_{10}(y)

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expand log_{10}((sqrt(x))/(2y^2))

expand

lo g_{10} (\frac{x}{2 y ^{2}})

lo g_{10} (x) - lo g_{10} (2) - 2 lo g_{10} (y)

Solution steps

lo g_{10} (\frac{x}{2 y ^{2}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{x}{2 y ^{2}}) = lo g_{10} (x) - lo g_{10} (2 y^{2})

= lo g_{10} (x) - lo g_{10} (2 y^{2})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (2 y^{2}) = lo g_{10} (2) + lo g_{10} (y^{2})

= lo g_{10} (x) - (lo g_{10} (y^{2}) + lo g_{10} (2))

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (y^{2}) = 2 lo g_{10} (y)

= lo g_{10} (x) - (lo g_{10} (2) + 2 lo g_{10} (y))

- (lo g_{10} (2) + 2 lo g_{10} (y)) : - lo g_{10} (2) - 2 lo g_{10} (y)

= lo g_{10} (x) - lo g_{10} (2) - 2 lo g_{10} (y)

9 lo g_{b} (x) + 8 lo g_{b} (z)

9.24 + lo g_{10} (\frac{0.15}{0.3})

lo g_{10} (\frac{x ^{9}}{y})

ln (\frac{97}{11})

ln (\frac{2 x ^{2} y}{x ^{4} + y ^{2}})

What is expand log_{10}((sqrt(x))/(2y^2)) ?
The solution to expand log_{10}((sqrt(x))/(2y^2)) is log_{10}(sqrt(x))-log_{10}(2)-2log_{10}(y)