What are the solutions to the equation 2x^2+7=7x ?

The solutions to the equation 2x^2+7=7x are x= 7/4+i(sqrt(7))/4 ,x= 7/4-i(sqrt(7))/4

Find the zeros of 2x^2+7=7x

The zeros of 2x^2+7=7x are x= 7/4+i(sqrt(7))/4 ,x= 7/4-i(sqrt(7))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 7 = 7 x

x = \frac{7}{4} + i \frac{7}{4}, x = \frac{7}{4} - i \frac{7}{4}

Solution steps

2 x^{2} + 7 = 7 x

Move

7 x

to the left side

2 x^{2} + 7 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 7 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

Simplify

(- 7)^{2} - 4 \cdot 2 \cdot 7 : 7 i

x_{1, 2} = \frac{- ( - 7 ) \pm 7 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 7 i}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 7 i}{2 \cdot 2}

x = \frac{- ( - 7 ) + 7 i}{2 \cdot 2} : \frac{7}{4} + i \frac{7}{4}

x = \frac{- ( - 7 ) - 7 i}{2 \cdot 2} : \frac{7}{4} - i \frac{7}{4}

The solutions to the quadratic equation are:

x = \frac{7}{4} + i \frac{7}{4}, x = \frac{7}{4} - i \frac{7}{4}

x^{4} - 12 x^{2} + 27

6 \cdot 24

8 x^{2} - 14 x + 5

4 x^{2} - 9 x + 7 = 0

\frac{3}{5 - 11 i}

What are the solutions to the equation 2x^2+7=7x ?
The solutions to the equation 2x^2+7=7x are x= 7/4+i(sqrt(7))/4 ,x= 7/4-i(sqrt(7))/4
Find the zeros of 2x^2+7=7x
The zeros of 2x^2+7=7x are x= 7/4+i(sqrt(7))/4 ,x= 7/4-i(sqrt(7))/4